Xn+1 = X + 0.25 Based on the relation above, write a code that calculates the values of Xn+1 for each value of n and gives the results for n=0, 5, 10, 15,... only. n=0,1,2,3,..,N, N=thw
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- For the following number patterns write the recurrence relation i) 5, 8.2, 11.4, 14.6, …. ii) 400, 50, 6.25, 0.781t(1) = 5 , t(n) = t(n/2) substitution recurrence relationExample 1) In R programming language: -Create a ordinal factor named “Height” containing – high, low, mid, low, mid, low, mid, high, mid, high. -Using a logical index, create new factor of only those from “Height”" greater than low. -Replace the last index in “Height” with veryHigh and create new factor with those greater than mid
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