xplain why x follows a binomial distabuton . blnsfead of using What probabilcty use to appoximate the distabution of X? Explain and state relevant para- meter value (5). ()Approximate the Probabulity that more than '200 customers' order pepperonL DA heur pizza. (4 Charactenstics) the bunomial distnbution istnbution Could you any

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
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Question
X sepresents the number of customers'who
order'pepperon on theur PUZza then X
At Paulis Pizzeria, Folo Dff all cusfomers
a random'Sample of 300 cusfomers. If
Quesfion?
order peppe
S randonSample of 300
roni on ther PUZza. Consider
a'bunomjal disfabution with
0.7
follows
D=300 and
ajexplain why X follows a bnomial
distnbut
bllnsfead of wsing the bunomial dustnbution
What probability disfnbution could you
useto appnximate the dista bution of
X? Explain and state y relevant
meter value (5).
() Approximate the Probabulity that more
than '200 customers' order pepperoni DA
heur puzza
(4'Charactenstics)
any
Pard-
Transcribed Image Text:X sepresents the number of customers'who order'pepperon on theur PUZza then X At Paulis Pizzeria, Folo Dff all cusfomers a random'Sample of 300 cusfomers. If Quesfion? order peppe S randonSample of 300 roni on ther PUZza. Consider a'bunomjal disfabution with 0.7 follows D=300 and ajexplain why X follows a bnomial distnbut bllnsfead of wsing the bunomial dustnbution What probability disfnbution could you useto appnximate the dista bution of X? Explain and state y relevant meter value (5). () Approximate the Probabulity that more than '200 customers' order pepperoni DA heur puzza (4'Charactenstics) any Pard-
C CM
CHAPTER 2
(EF,.
1
n-1
n-1
Position of the pth percentile
(n+1)
%3D
100
CHAPTER 3
Sxy
, Sxy =
SxSy
regression line: y=a+bx, b r(), a y-bx
n-1
CHAPTER 4
For any two events A and B
P(AUB) = P(A) + P(B) – P(A B)
and if A and B are mutually exclusive events, then
• P(A“) = 1– P(A)
P(AN B) = 0
If A and B are 2 independent events, then
P(AN B) = P(A) x P(B)
Conditional probability: If A and B are 2 events, then
P(ANB)
P(A|B) =
P(B)
Bayes Rule:
P(S\A)
P(SNA)
%3D
P(Si).P(A|St)
%3D
P(A)
E-1 P(S:).P(A|Si)
n!
• pn =
(n-r)!
n!
C =
r!(n-r)!
E (X) = E, xip(x,),
v(X) = E, x7p(x;) -E, x;p(x;))' = E(Xx²) – (E(X))?
CHAPTER 5
Distribution
Probability Mass Function
Mean
Variance
Binomial
P(X=x)=C#p°(1-p*, x= 0,1,..n
пр
пр(1 - р)
Poisson
P(X = x) = '
,x = 0,1,...
M(N-MN-
Hypergeometric
P(X=x)3D
CN
N
N-
Approximations:
If n/N <0.05(N/n 220), then the hypergeometric distribution can be approximated by the binomial
distribution with parameters n and p = MIN.
If p is small, n is large, and np <7, then the binomial distribution can be approximated by the Poisson
distribution with u = np.
MacBook Air
Transcribed Image Text:C CM CHAPTER 2 (EF,. 1 n-1 n-1 Position of the pth percentile (n+1) %3D 100 CHAPTER 3 Sxy , Sxy = SxSy regression line: y=a+bx, b r(), a y-bx n-1 CHAPTER 4 For any two events A and B P(AUB) = P(A) + P(B) – P(A B) and if A and B are mutually exclusive events, then • P(A“) = 1– P(A) P(AN B) = 0 If A and B are 2 independent events, then P(AN B) = P(A) x P(B) Conditional probability: If A and B are 2 events, then P(ANB) P(A|B) = P(B) Bayes Rule: P(S\A) P(SNA) %3D P(Si).P(A|St) %3D P(A) E-1 P(S:).P(A|Si) n! • pn = (n-r)! n! C = r!(n-r)! E (X) = E, xip(x,), v(X) = E, x7p(x;) -E, x;p(x;))' = E(Xx²) – (E(X))? CHAPTER 5 Distribution Probability Mass Function Mean Variance Binomial P(X=x)=C#p°(1-p*, x= 0,1,..n пр пр(1 - р) Poisson P(X = x) = ' ,x = 0,1,... M(N-MN- Hypergeometric P(X=x)3D CN N N- Approximations: If n/N <0.05(N/n 220), then the hypergeometric distribution can be approximated by the binomial distribution with parameters n and p = MIN. If p is small, n is large, and np <7, then the binomial distribution can be approximated by the Poisson distribution with u = np. MacBook Air
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