y = {0srs1} 10 y = {-2sx<0} x2 - 4 -5 56 y = x3 - 8 y = - {6

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.1: Simplifying Fractions
Problem 33WE
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Answer the following from the picture below: ● Domain and Range ● End Behavior ● Describe any discontinuity by explaining where it is and what type it is. ● Intervals of increasing and decreasing (to nearest .5 is sufficient) ● Domain and Range ● End Behavior ● Describe any discontinuity by explaining where it is and what type it is. ● Intervals of increasing and decreasing (to nearest .5 is sufficient)
y= {0sxs1}
10
y = {-2sx<0}
x - 4
-5
56
y =
-{25x54}
y =
- {6<x59}
-20
-15
-10
-5
V6x – 36
10
-5
Transcribed Image Text:y= {0sxs1} 10 y = {-2sx<0} x - 4 -5 56 y = -{25x54} y = - {6<x59} -20 -15 -10 -5 V6x – 36 10 -5
Expert Solution
Step 1

1/x

1)Domain :(0,1]

Range:[1, infinity)

2) end behaviour: not possible since it is not polynomial

3) discontinuity of function at 0

4)

intervals of increase

intervals of decrease

(0,1)

 

ii)1/(x^2-4)

1)domain

(−2,0)

range

(−∞,−14)=(−∞,−0.25)

 

2)end behaviour: not possible since it is not polynomial

3)

discontinuity of function at x=-2,2

4)

intervals of increase

(−2,0) U(−2,0)

intervals of decrease

 

iii)56/(x^3-8)

1)

DOMAIN

(2,4]

range

[1,∞)

2)End behavior:

The function entered is not a polynomial

3)Discontunity of function:2,-2

4)intervals of increase

intervals of decrease

(2,4)

 

 

 

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