Y dA + x10 + y10 + 10 D over the domain D = [-3, 2] × [–-1, 1].

Q: elica Find the missing y%3D Z= y 76° DELL -> esc & ! 6. 4 1 2 e

A: Given:

Q: %3D x2+7 X2 +7 to flx1-メ= LtzX as xI oc ニ I + 7/x?

A:

Q: (D3 - 3D - 2)y =0; when x =0, y=0, y' = 9, y” = 0.

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Q: -2xy 3) y' = iy = -5 when x = 2 Ans: exact; x²y + y = -25

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Q: 3 1) y=--x-1 2 A) B) C) D)

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Q: (D³ + 4D² + 9D + 10)y - 24 e*; when x = 0, y = 0, y' = -4, y" = 10. %3D

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Q: 5. (D³2D+4)y=0; y = -2, Dy = 8, D²y = 0, when x = 0.

A:

Q: 9. x = 3t + 3 and y = t - 3 for 1<t< 5 Domain:

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Q: [ 0 y-y² y-y² (y - y² - x²) dxdy

A: Given equation: ∫01∫-y-y2y-y2(y-y2-x2) dx dy

Q: Solve by reduction of order. Find y2 and y (x² + 1)y" – 2xy' + 2y = 0 yı = x -

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Q: Q Find the domain of y 1- Vx + V+ 3x-x – 3

A:

Q: O A y = -s – 1)? y = -412 + 1 y=D -쇼z2 + 1 O D. y Oc. |

A: Here we have to find the equation of parabola.

Q: (D³ – D)y = –2(1+x) + 4e* – 6e¬* + 96e3x -

A: Given- D3-Dy=-21+x+4ex-6e-x+96e3x To Solve- The above differential equation.

Q: Q1\ Simplify (2+ j5) + 3- j4 5(7+ j2) -j(4- j6), expressing the result in the form x +jy.

A: since you have asked multiple questions, we will solve the first question for you if you want any…

Q: æ = 4;y = t-1»Y t² – 1|

A: Use the following derivative formulas:ddxxn=nxn-1ddxfxgx=ddxfxgx-ddxgxfxgx2ddx ( f(g(x) ) = f'…

Q: J 5(x) =-J5(x) ylgn O İhi O

A: We have to solve given problem:

Q: (r2+2rt-4t2)dr-(r2-8rt-4t2)dt=0

A:

Q: (D²-3D-2)y = 0 Find y when x = In 2 when x=0, y'= 9, Y=0, y=0 4.

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Q: runction ov 1 y=- -1, 0] x+2' A) -2 В) 0 D) C) 4.

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Q: 2. (D² + 8D + 16)y = 1-e4x

A:

Q: 2t + 7 f(t) = t- 3 %3D h(n) = - 2n2-3n+1 %3D f(h(-1)) =

A: Here we have two functions f(t) and h(n), we want to find the value of f(h(—1)). To find f(h(—1)),…

Q: y" - 2y' + y = 4e-t + 2et, where y(0) = -1, y'(0) = 2

A:

Q: 11. x = 2t – 2 and y = -t + 2 for 0 <t < 4 | Domain:

A: In this question we have to find the Domain.

Q: 2r² + 3sr - 2r t6s)s t s(st 2r -1) dr = 0 %3D

A:

Q: f(x) =D V4- x2 1는 Jf %3D (-2,2) .1 (-00, –2) U (2, 0) 2 (-0, 2] U [2, c0) 3 [-2,2] .4

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Q: x=t-2 and y= t t-2

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Q: Ve da 6. Given x=- 1 a = 3x +2x-1 and and y=- find 2 de c-4

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Q: 4) y =6 from x = 1 to x =3 + 2x A) - 3 D B)

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Q: Q.2 a. Find the Domain for y-4-!

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Q: 7. x+y (2r+2y-x) at (0, %) +y 4 at (-3v3, 1) 8.

A: The function f(x,y) is a rule that associates or fixes a number to a particular point (x,y). The…

Q: 1. (D 2 + 3D + 2)y = 4t 2 By: (a) reduction of order, and (b) variation of parameters.

A:

Q: (D³ + 7D² + 19D + 13)y = 0 when x = 0,y = 0,y' = 2,y" = -12 %3D %3D

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Q: u? – 1 du J2x u² + 1 3x - 56. g(x) :

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Q: y - 3y = 8(t - 2), y(0) = 0 %3D

A: We have to solve the given ode using laplace transform.

Q: I Y=t5メPYove th y-2(21くるど

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Q: f(t) = t² – 3t + 5 Ans. 5s2 – 3s + 2

A: As per our guidelines we are supposed to solve only first question. Kindly repost other question as…

Q: Q.2 R ex2-2 dxdy, where R between x = -y, y = 0 and x = -! -3, y = -9

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Q: (t+1)y" – (t + 2)y' + y = 0 or t > -1.

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Q: Q2/A/ Find " X" from equation r2 = 8(2tan20 + 1) %3D

A: Please rate and feel free to ask any query about any part of the question.

Q: e3x (D³ – 3D² + 2D)y 1+ex

A: The given question can be solved as shown in step2.

Q: I. Perform the indicated operatic Z₁ =3e7 a) Z₁Z₂

A:

Q: 2s -5t f(s,t) = %3D 4s +t %3D f =

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: y" - y' - 6y=t²e³t — 4t², y(0) = 0, y' (0) = -1

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Q: 3.) y=exp(-t2) with an inflection point at t=-.7 and .7

A: Using the second derivative test to find the inflection points(if any) for a given function. Second…

Q: 8. f(x) = (2x³ + 9x)³ 9. s(t) = (5ª +2)(t² – 1)3/2 %3D

A:

Q: (r² + y² )²dydx • Evaluate:

A: Given: ∫03∫09-x2x2+y252dydx

Q: Express (2xy + 2x – 1) – (x² – y² – 2y)i in terms of z & Z then simplify.

A:

Q: 5. (D² + 1)y = 10e2x; when x = 0, y = 0,y' = 0 %3D

A: Find complementary function and particular integral then solution is given by y(x)= CF + PI .

Q: (D' +5D +3D-9)y = 0; when x = 0, y =-1, when x = 1, y = 0 and also as x→ 0, y = 0

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Q: - 3 Find y' for y = 2x- 2x-1. y' =D %3D

A:

Riemann Sum

Riemann Sums is a special type of approximation of the area under a curve by dividing it into multiple simple shapes like rectangles or trapezoids and is used in integrals when finite sums are involved. Figuring out the area of a curve is complex hence this method makes it simple. Usually, we take the help of different integration methods for this purpose. This is one of the major parts of integral calculus. 

Riemann Integral

Bernhard Riemann's integral was the first systematic description of the integral of a function on an interval in the branch of mathematics known as real analysis.