y = (t² – 2)². a²y = t2 dx²

Q: dy y² tion + dx x² है || Y 8

A:

Q: dy Q1: - find ay/dx for y = 5cscx3

A:

Q: d/dx (dy/dx)` x=1, , where y = x3 + 2x - 11

A: To find: The value of ddxdydx at x=1. Given: The function is y=x3+2x-11. Formula used: Power rule of…

Q: dy for y = x2 - 8. Q2) Find dx x-1

A:

Q: d'y d²y dx2 dy 18y = 0 dx 2 +9+ dx3

A: We have to solve given problem:

Q: dy 3. + y = e3x dx

A:

Q: Find dx2 where y +xy%3D5 Ry dx2

A: Given function is Differentiating both sides with respect to x, we get

Q: d®y dx + 17 + 88 + 144y = 0 dx dx2

A: Differential equations

Q: d'y dr2 dy - 2 +y=3 e4x, given y(0) dx 1 and y'(0) =4; 3.

A:

Q: 6. x2 +7 y = 8. dy dx II

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Q: dy :- 15x²y and y = 4 when x = -4 dx

A: To solve the initial value problem  dydx = -15 x2ydyy = -15x2 dx

Q: dy from the equation 3xy2 + 4 dx Evaluate y _ y-5 11 when x =1 2x2 – 1

A:

Q: dy/dx=y2/3

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Q: dy y = (3x2 + x-2)-1; dx

A:

Q: d³y and dx ' dx2 dy d²y Find from: dx3 3. x = V1 - t and y = t³ – 3t |

A:

Q: calculate d2y/dx2 when y=3/x

A:

Q: d²y ex 1. Find dx2 for y = %3D (2x²–3)

A: According to our terms and conditions I have solved first question for next question repost

Q: Find dy dx² for x =t2 + 1, y = t +t³. d²y dx² ||

A:

Q: d²y + y = tan x dx2

A: Solution of differential equations

Q: Find dx² given d²y given X² – y³ = 5.

A: Given that: x2-y3=5

Q: Solve the differential equation in Exercises

A: Given 17. dydx=2x1-y2 ,   -1<y<1 18. dydx=e2x-yex+y

Q: y = (ax-1) (6x.+5]%3 find dy dx 10

A:

Q: Q7 Find dy using substitution: dx y = csc-(x3 + 1)

A: Put u=x3+1. Then, du=3x2dx Therefore, the expression y=cosec-1(x3+1) becomes,…

Q: a) Find dy =dx when y=(x² – 5x +7)*

A:

Q: colve dx+. y 2х y²-3x² -dy=0 y?

A: Given 2xy3dx+y2-3x2y2dy=0Need to solve

Q: Find dy/dx.  s = t4 - csc t + 14

A: Consider  s=t4−csct+14

Q: 4. Determine dx2 - of the function y = v1– 2xt + t² |t= constant

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Q: dy. dx2 y = -6x2 + 7x Calculate d²y dx2

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Q: d²y + y = 0 dx2

A:

Q: d?y dy + 2- dx 4x dx2

A: given differential equation :

Q: Find y dx2 in terms of x and y. y7 = x° dy dx?

A: Remark: we know that  d/dx (xn ) = n xn-1 , where n is any integer except -1.

Q: d²y Find dx ,where y = 5x – 3x²,

A: we have to find the second derivative at x=1

Q: 22 d'y dx² dy 7x- +16y=0 dx

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Q: calculate  d2y dx2 . y = −  4/ x2

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Q: dy Find for dx 1 y=-=-72-8√x x

A:

Q: dy Find dx2 x = t – 7, y =t - t2 dy

A: See the details solution below

Q: Find dy =dx when y= (x² – 5x + 7)*

A: Derivative of the function

Q: (d) , 2x Vx2 + 2 dx -5 (e) Si J5-y dy

A:

Q: Ε. = Oy dx 47&a• (x +y)3 2

A: Introduction: The definite integration is the integration where we put limits over integration.…

Q: dy Calculate dx2 2 y =

A: To calculate d^2y/dx^2

Q: dy – y – 5x* – 3x² + 2x = 0 dx - -

A:

Q: calculate d2y/dx2 when y=-2/x2

A: Given: y=-2x2

Q: Find d2y/dx2 for y = tln(t) + 9t, x = tet + 1.

A: Given,        y=tlnt+9t  and  x=tet+1

Q: dy 3x + et Find for y = dx x2 – 5 Ans=

A: y=3x+exx2-5To find dydx

Q: La S* (16 – y – y) dy dx = 47. 512

A: ∫-22∫x28-x2(16-y-y) dy dx

Q: y 2t3-5t2 +3, find dy/dt

A: We have to find the derivative of the given function.

Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as: