Answered: y - y² = 1 – 0.5x | 1 m 1 m - 2 m-…

y - y² = 1 – 0.5x | 1 m 1 m - 2 m- Figure Q10 a) the moment of inertia of the shaded area about the x axis. b) the moment of inertia of the shaded area about the y axis.

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter9: Moments And Products Of Inertia Of Areas

Section: Chapter Questions

Problem 9.8P: Using integration, compute the polar moment of inertia about point O for the circular sector. Check...

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Free Body Diagram

The system of forces acting on a body tends to either rotate it or make the body undergo motion. In general, when an external agent exerts a force on a body, the body undergoes translational motion and rotational motion. The body has six degrees of freedom under the influence of that force. Here, three degrees of freedom are from the translational motion while the other three are from the rotation motion. However, sometimes the bodies are not allowed to undergo any motion and are fixed, under such conditions the body is said to be constrained.

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Figure Q10 shows the shaded area with the equation given. Calculate:
y² = 1 – 0.5x
1 m
1 m
-2 m–
Figure Q10
a) the moment of inertia of the shaded area about the x axis.
b) the moment of inertia of the shaded area about the y axis.

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