yle's true weight is 600 N (magnitude), and her apparent weight at a certain time is 500 N magnitude). What is her acceleration at this time? Use g 10.0 m/s. (Hint: What is her mass and what is the net force?) Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.

Glencoe Physics: Principles and Problems, Student Edition
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ISBN:9780078807213
Author:Paul W. Zitzewitz
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Chapter1: A Physics Toolkit
Section: Chapter Questions
Problem 7STP
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Kyle's true weight is 600 N (magnitude), and her apparent weight at a certain time is 500 N
(magnitude). What is her acceleration at this time? Use g = 10.0 m/s. (Hint: What is her mass and
what is the net force?)
Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not
include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the
question statement.
Transcribed Image Text:Kyle's true weight is 600 N (magnitude), and her apparent weight at a certain time is 500 N (magnitude). What is her acceleration at this time? Use g = 10.0 m/s. (Hint: What is her mass and what is the net force?) Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.
Expert Solution
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The true weight is the original weight of the person while the apparent weight is the reaction force by the ground acting on the person. Let   Fscale be the apparent weight and let Fg be the original weight of the person.Let m be her mass and let ay be the required acceleration. Now, by Newton's Second law of motion,(Fy)=may-Fg+Fscale=Fggay......(1).....(Apparent weight is the reaction force, hence it acts upwards)

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