You are designing a weather rocket that is to be launched from rest, vertically upward off the ground. The engine burn will last for 2.5 s. If the positive y direction is upward, away from the ground, then the acceleration during the engine burn (including the influence of gravity) is ay(t)=bt^3 with b = 16.79 m/s^5 and t the time from engine ignition. After the engine burns out, the acceleration is then ay(t)=−g. How long after the engine burns out does the rocket take to reach its maximum height
You are designing a weather rocket that is to be launched from rest, vertically upward off the ground. The engine burn will last for 2.5 s. If the positive y direction is upward, away from the ground, then the acceleration during the engine burn (including the influence of gravity) is ay(t)=bt^3 with b = 16.79 m/s^5 and t the time from engine ignition. After the engine burns out, the acceleration is then ay(t)=−g. How long after the engine burns out does the rocket take to reach its maximum height
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You are designing a weather rocket that is to be launched from rest, vertically upward off the ground. The engine burn will last for 2.5 s. If the positive y direction is upward, away from the ground, then the acceleration during the engine burn (including the influence of gravity) is ay(t)=bt^3 with b = 16.79 m/s^5 and t the time from engine ignition. After the engine burns out, the acceleration is then ay(t)=−g. How long after the engine burns out does the rocket take to reach its maximum height?
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