You are doing a genetics experiment with the fruit fly. In the "F1" generation, you cross two true-breeding flies. The female parent is brown and wingless and the male parent is black with normal wings All of the flies in the F1 generation are brown and have normal wings. Indicate the color alleles as "B" and "b" the wing alleles by the letters "N" and "n". Assume these genes are not on X chromosome. male. a. Show the genotype of the flies in the P generation are: female_ and b. The genotype of the flies in the F1 generation is:_ c. You now take an F1 female and cross her to a true-breeding black, wingless male. This male's genotype is: d. You count 1600 offspring in the F2 generation. When you count the F2 generation, you really get: 85 brown winged flies 728 black winged flies 712 brown wingless flies 75 black wingless flies What happened here? Explain your results. Draw and show every step clearly

You are doing a genetics experiment with the fruit fly. In the "F1" generation, you cross two true-breeding flies. The female parent is brown and wingless and the male parent is black with normal wings All of the flies in the F1 generation are brown and have normal wings. Indicate the color alleles as "B" and "b" the wing alleles by the letters "N" and "n". Assume these genes are not on X chromosome. male. a. Show the genotype of the flies in the P generation are: female_ and b. The genotype of the flies in the F1 generation is:_ c. You now take an F1 female and cross her to a true-breeding black, wingless male. This male's genotype is: d. You count 1600 offspring in the F2 generation. When you count the F2 generation, you really get: 85 brown winged flies 728 black winged flies 712 brown wingless flies 75 black wingless flies What happened here? Explain your results. Draw and show every step clearly

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter14: Chromosomes And Human Inheritance

Section: Chapter Questions

Problem 3GP: Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With...

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Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele?
A researcher crosses two white-flowered lines ofAntirrhinum plants as follows and obtains the followingresults:pure line 1 × pure line 2↓F1 all whiteF1 × F1↓F2 131 white29 reda. Deduce the inheritance of these phenotypes; useclearly defined gene symbols. Give the genotypes ofthe parents, F1, and F2.b. Predict the outcome of crosses of the F1 with eachparental line.
Morgan first suggested that theoriginal white-eyed male had two copies of the white-eye allele. Inthis problem, let’s assume that he meant the fly was XwYwinstead ofXw Y What crosses would need to be made to rule out the possibility thatthe Y chromosome carries a copy of the eye color gene?
The recessive, X-linked z1mutation of the Drosophilagene zeste (z) can produce a yellow (zeste) eye coloronly in flies that have two or more copies of the wildtype white (w) gene. Using this property, tandem duplications of the w+ gene called w+Rwere identified.Males with the genotype y+ z1w+R spl+ / Y thus havezeste eyes. These males were crossed to females withthe genotype y z1 w+R spl / y+ z1 w+R spl+. (These fourgenes are closely linked on the X chromosome, in theorder given in the genotype, with the centromere tothe right of all these genes: y = yellow bodies; y+ =tan bodies; spl = split bristles; spl+ = normal bristles.) Out of 81,540 male progeny of these females,the following exceptions were found:Class A 2430 yellow bodies, zeste eyes, wild-type bristlesClass B 2394 tan bodies, zeste eyes, split bristlesClass C 23 yellow bodies, wild-type eyes, wild-type bristlesClass D 22 tan bodies, wild-type eyes, split bristlesa. What were the phenotypes of the remainder of the81,540 males…
A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) This woman is phenotypically normal. Does thissurprise you? Why or why not? Under what circumstancesmight you expect a phenotypic effect of such arearrangement?
You have a female snail that coils to the right, but you do not knowits genotype. You may assume that right coiling (D) is dominant toleft coiling (d). You also have male snails of known genotype.How would you determine the genotype of this female snail? Inyour answer, describe your expected results depending on whetherthe female is DD, Dd, or dd.
Three genes in fruit flies affect a particular trait, andone dominant allele of each gene is necessary to get awild-type phenotype.a. What phenotypic ratios would you predict amongthe progeny if you crossed triply heterozygous flies?b. You cross a particular wild-type male in successionwith three tester strains. In the cross with one testerstrain (AA bb cc), only 1/4 of the progeny are wildtype. In the crosses involving the other two testerstrains (aa BB cc and aa bb CC), half of the progeny are wild type. What is the genotype of thewild-type male?
A tomato geneticist attempts to assign five recessivemutations to specific chromosomes by using trisomics.She crosses each homozygous mutant (2n) with each ofthree trisomics, in which chromosomes 1, 7, and 10 takepart. From these crosses, the geneticist selects trisomicprogeny (which are less vigorous) and backcrosses themto the appropriate homozygous recessive. The diploidprogeny from these crosses are examined. Her results, inwhich the ratios are wild type:mutant, are as follows:Which of the mutations can the geneticist assign towhich chromosomes? (Explain your answer fully.)
Two mothers give birth to sons at the same time at a busy urbanhospital. The son of mother 1 has hemophilia, a disease causedby an X-linked recessive allele. Neither parent has the disease.Mother 2 has a son without hemophilia, despite the fact thatthe father has hemophilia. Several years later, couple 1 suesthe hospital, claiming that these two newborns were swappedin the nursery following their birth. As a genetic counselor, youare called to testify. What information can you provide the juryconcerning the allegation?
In Drosophila, males from a true-breeding stock withraspberry-colored eyes were mated to females from atrue-breeding stock with sable-colored bodies. In theF1 generation, all the females had wild-type eye andbody color, while all the males had wild-type eyecolor but sable-colored bodies. When F1 males andfemales were mated, the F2 generation was composedof 216 females with wild-type eyes and bodies, 223females with wild-type eyes and sable bodies, 191males with wild-type eyes and sable bodies, 188 maleswith raspberry eyes and wild-type bodies, 23 maleswith wild-type eyes and bodies, and 27 males withraspberry eyes and sable bodies. Explain these resultsby diagramming the crosses and calculating any relevant map distances
In humans, color vision depends on genes encodingthree pigments. The R (red pigment) and G (green pigment) genes are close together on the X chromosome,whereas the B (blue pigment) gene is autosomal. A recessive mutation in any one of these genes can cause colorblindness. Suppose that a color-blind man married awoman with normal color vision. The four sons from thismarriage were color-blind, and the five daughters werenormal. Specify the most likely genotypes of both parents and their children, explaining your reasoning. (Apedigree drawing will probably be helpful.) (Problem 50is by Rosemary Redfield.)
In a cross between a white-eyed female (ww) and a red-eyed male (w+Y), nearly all the progeny were either red-eyed females (w+w) or white-eyed males (wY). However, about 1 in every 2000 F1 flies had an "exceptional phenotype" and was either a white-eyed female or red-eyed male. How did Bridges explain this unexpected result? A) Crossing over B) Incomplete cytokinesis C) Incorrect synapsis D) Nondisjunction E) Pseudoautosomal region