You are given the head of a linked list. Delete the middle node, and return the head of the modified linked list. The middle node of a linked list of size n is the [n / 2] th node from the start using 0-based indexing, where [x] denotes the largest integer less than or equal to x. • For n = 1, 2, 3, 4, and 5, the middle nodes are 0, 1, 1, 2, and 2, respectively. * Definition for singly-linked list. * struct ListNode {
You are given the head of a linked list. Delete the middle node, and return the head of the modified linked list. The middle node of a linked list of size n is the [n / 2] th node from the start using 0-based indexing, where [x] denotes the largest integer less than or equal to x. • For n = 1, 2, 3, 4, and 5, the middle nodes are 0, 1, 1, 2, and 2, respectively. * Definition for singly-linked list. * struct ListNode {
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![You are given the head of a linked list. Delete the middle node, and return the head of the
modified linked list.
The middle node of a linked list of size n is the In / 2] th node from the start using 0-based
indexing, where [x] denotes the largest integer less than or equal to x.
For n =
1, 2, 3, 4, and 5, the middle nodes are 0, 1, 1, 2, and 2, respectively.
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
ListNode* deleteMiddle(ListNode* head) {
//write your code here
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4570490-8ffb-404a-806b-a5948e8b1c6f%2Fa70f4de6-344e-4920-9f3c-9c4cf108e415%2Fpdkkge_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You are given the head of a linked list. Delete the middle node, and return the head of the
modified linked list.
The middle node of a linked list of size n is the In / 2] th node from the start using 0-based
indexing, where [x] denotes the largest integer less than or equal to x.
For n =
1, 2, 3, 4, and 5, the middle nodes are 0, 1, 1, 2, and 2, respectively.
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
ListNode* deleteMiddle(ListNode* head) {
//write your code here
}
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