You are studying a single-gene locus with two alleles in a population that is in Hardy–Weinberg equilibrium. Examination of a large sample of individuals from the population reveals there are six times as many heterozygotes as there are homozygote recessive individuals in this population. What is the frequency of the recessive allele? I don't know how to start his calculation with just a ratio of 6:1 I found an answer online that says the frequency of q=0.25 but the calculations (below) don't make sense to me. Please help me. What is the answer and how do I get to it? Hardy-Weinberg equation p2+2pq+q2=1 2pq/q2= 6/1 2p= 6q 2(1-p)= 6q 2-2q=6q q=0.25

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter19: Population Genetics And Human Evolution
Section: Chapter Questions
Problem 8QP: How Can We Measure Allele Frequencies in Populations? In a population where the females have the...
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You are studying a single-gene locus with two alleles in a population that is in Hardy–Weinberg equilibrium. Examination of a large sample of individuals from the population reveals there are six times as many heterozygotes as there are homozygote recessive individuals in this population. What is the frequency of the recessive allele?

I don't know how to start his calculation with just a ratio of 6:1 I found an answer online that says the frequency of q=0.25 but the calculations (below) don't make sense to me. Please help me. What is the answer and how do I get to it?

Hardy-Weinberg equation p2+2pq+q2=1

2pq/q2= 6/1

2p= 6q

2(1-p)= 6q

2-2q=6q

q=0.25

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