You are underwater, on the seafloor, looking up. Use n=1.33 for the index of refraction of water. At what range of angles, as measured above the seafloor, can you NOT see out of the water? (You will need a carefully labeled diagram showing just where the light is coming from, and a reasoned explanation of why your answer is correct.)

You are underwater, on the seafloor, looking up. Use n=1.33 for the index of refraction of water. At what range of angles, as measured above the seafloor, can you NOT see out of the water? (You will need a carefully labeled diagram showing just where the light is coming from, and a reasoned explanation of why your answer is correct.)

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter38: Refraction And Images Formed By Refraction

Section: Chapter Questions

Problem 87PQ

See similar textbooks

Similar questions

Light enters a prism of crown glass and refracts at an angle of 5.00 with respect to the normal at the interface. The crown glass has a mean index of refraction of 1.51. It is combined with one flint glass prism (n = 1.65) to produce no net deviation. a. Find the apex angle of the flint glass. b. Assume the index of refraction for violet light (v = 430 nm) is nv = 1.528 and the index of refraction for red light (r = 768 nm) is nr = 1.511 for crown glass. For flint glass using the same wavelengths, nv = 1.665 and nr = 1.645. Find the net dispersion.
Light is incident on a prism as shown in Figure P38.31. The prism, an equilateral triangle, is made of plastic with an index of refraction of 1.46 for red light and 1.49 for blue light. Assume the apex angle of the prism is 60.00. a. Sketch the approximate paths of the rays for red and blue light as they travel through and then exit the prism. b. Determine the measure of dispersion, the angle between the red and blue rays that exit the prism. Figure P38.31
A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.50) at ail angle of 30.0 with respect to the normal (Fig. P22.18). (a) Find the angle of refraction at the lop surface. (b) Find the angle of incidence at the bottom surface and the refracted angle. (c) Find the lateral distance d by which the light beam is shifted. (d) Calculate the speed of light in the glass and (e) the time required for the light to pass through the glass block. (f) Is the travel time through the block affected by the angle of incidence? Explain.
An optical fiber has an index of refraction n and diameter d. It is surrounded by vacuum. Light is sent into the fiber along its axis as shown in Figure P34.31. (a) Find the smallest outside radius Rmin permitted for a bend in the fiber if no light is to escape. (b) What If? What result does part (a) predict as d approaches zero? Is this behavior reasonable? Explain. (c) As n increases? (d) As n approaches 1? (c) Evaluate Rmin assuming the fiber diameter is 100 m and its index of refraction is 1.40. Figure P34.31
When light is incident normally on the interface between two transparent optical media, the intensity of the reflected light is given by the expression S1=(n2n1n2+n1)2S1 In this equation, S1 represents the average magnitude of the Poynting vector in the incident light (the incident intensity), S1 is the reflected intensity, and n1 and n2 are the refractive indices of the two media. (a) What fraction of the incident intensity is reflected for 589-nm light normally incident on an interface between air and crown glass? (b) Does it matter in part (a) whether the light is in the air or in the glass as it strikes the interface?
In an optical fiber, what can be said about the index of refraction of the core versus the cladding and the angle of reflection, θ, inside the fiber relative the critical angle, θc? Question 9 options: ncore > ncladding ; θ > θc ncore > ncladding ; θ < θc ncore < ncladding ; θ > θc ncore < ncladding ; θ < θc
What is the critical angle for the interface between water and diamond? The index of refraction of diamond is 2.42. To be internally reflected, the light must start in which material?
Snell’s Law relates the angle of incidence with the angle of refraction as n1 sin θ1 = n2 sin θ2. If a laser beam of 650 nm (red light) travels through the air and enters the water at an angle of 30 degrees with respect to the normal, what angle does the refracted ray make with the vertical? What is the wavelength of the red light in water?
A beam of light is incident on a hemispherical prism at an angle, theta, as shown in the figure. If the index of refraction of the prism is 1.60, what is the critical angle (in degrees) for no transmitted light out of the bottom of the prism? Assume the index of refraction for air is 1.00 and the index of refraction for the water is 1.33.
What is the minimum index of refraction for a material that is going to be used to make binoculars? (The material must have an index of refraction large enough that total internal reflection occurs at 45°.) Will the binoculars made of the material you just calculated work underwater? If not, what is the minimum index of refraction for binoculars that would work underwater? Please sketch the situation, if you can, thanks!