You have 150.0 mL of a 0.877 M solution of Ce(NO₂),. X What mass (in grams) of Ce(NO₂), would be required to make the solution? What is the concentration of the nitrate ions in the solution? If the original solution was diluted to 350.0 mL, what would be the new concentration of the Ce(NO₂), in the solution?

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A: mol = concentration  *  volume / 1000mol of NaOH  =  (1.3400*10^(-1) * 3.37*10^1)/1000 =0.0045158…

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