You have N boxes in Samosas, where each box is a cube. To pack the box, you need to use a rubber band (pseudo-circular, elastic band) by placing it next to the box (4 faces of a cube). The rubber band A (R1, R2) has an initial radius of R1 and can be expanded in size up to R2 without breaking. You can pack a cubic box of side length L using a 4 * L round rubber band (see Notes for clarity). Given the M-band bands and their first radius and the main radius, we need to match (provide) some rubber bands and boxes. The box needs at least one rubber band to pack and of course, each rubber band can be used to pack at least one box. Find the maximum number of boxes we can pack. Answer this in python programming language.
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- can you solve this please? Adopt appropriate Java animation code to implement the video in the file “test4.wmv” and given that the parametric equation for a circle. x=r*cos(t) y=r*sin(t) with t in range [0, 2p] and r is the radius of the circle. (the circle goes in a loop like in the images, i did my best to try to explain it , please try to do it ) and here is a sample of what they want me to use : package javaapplication1;import java.awt.*;import java.awt.event.*;import javax.swing.*;import java.awt.geom.*;import java.util.Random;import javax.imageio.*;import java.io.File;import java.io.IOException;import java.awt.image.BufferedImage;import java.awt.event.*;import java.util.Calendar; public class JavaApplication1 extends JApplet { public static void main(String[] args) { JFrame frame=new JFrame(); frame.setTitle("hello"); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JApplet applete =new JavaApplication1(); applete.init();…You are given a grid of size n ×m and within that grid there is a horizontal rod (arbitrary widthbut height of 1). You aim is to locate it. The only thing you can use to find the location of the rod is makequeries of the form IsPresent (x1, y1, x2, y2) where x1 ≤x2, y1 ≤y2. This returns True if part of the rod ispresent in the grid from (x1, y1) to (x2, y2) and False if not. See figures below. Design an algorithm whichuses queries O(log(n +m)) times to find the location of the rod, i.e., the leftmost coordinates and rightmostcoordinates. Hint: consider using binary search in your algorithm.I Need help on this question, I was also inform that I do not need to use "StringBuilder" for this question: In the game Rock Paper Scissors, two players simultaneously choose one of threeoptions: rock, paper, or scissors. If both players choose the same option, then theresult is a tie. However, if they choose differently, the winner is determined asfollows:•• Rock beats scissors, because a rock can break a pair of scissors.•• Scissors beats paper, because scissors can cut paper.•• Paper beats rock, because a piece of paper can cover a rock.Create a game in which the computer randomly chooses rock, paper, or scissors.Let the user enter a number 1, 2, or 3, each representing one of the three choices.Then, determine the winner. Save the application as RockPaperScissors.java.(In the chapter “Characters, Strings, and the StringBuilder,” you will modify thegame so that the user enters a string for rock, paper, and scissors, rather than justentering a number.)
- The map file holds a bunch of rectangles. Some of the rectangles are solid, and you can think of them like crates in a warehouse. They can be enclosed by a non-solid rectangle, and those rectangles are just there to make theintersection testing and such go faster. If a line doesn't cross a non-solid rectangle, then it cannot hit any rectangle inside it. Nice! The format is:Solid(1)/Nonsolid(0) x_min y_min x_max y_max (list of children iff not solid) The list of children are line numbers (the lines start at 0) of solid rectangles inside the non-solid rectangle. Solid rectangles do not have children. All non-solid rectangles must have children. Here's a sample file:0 0 0 100 100 1 21 1.1 1.0 1.2 1.31 10 10 11 110 50 60 70 80 40 55 65 65 75 51 56 66 64 74 The first line (line 0) is a non-solid rectangle with two children (the next two rows, lines 1 and 2). The first rectangle ranges from (0,0) to (100,100). The children of it are both small solid rectangles, the first is only .1 x .3,…Can you implement the Student class using the concepts of encapsulation? A solution is placed in the "solution" section to help you, but we would suggest you try to solve it on your own first. You are given a Student class in the editor. Your task is to add two fields: ● String name ● String rollNumber and provide getter/setters for these fields: ● getName ● setName ● getRollNumber ● setRollNumber Implement this class according to the rules of encapsulation. Input # Checking all fields and getters/setters Output # Expecting perfectly defined fields and getter/setters. There is no need to add constructors in this class.JAVA SWINGI have definied a straight TUBE as: int rectWidth = 25; // replace 50 with the desired width of the rectangleint rectHeight = 200; // replace 200 with the desired height of the rectangleint rectX = (this.getWidth() - rectWidth) / 2;int rectY = (this.getHeight() - rectHeight) / 2;game.fillRect(rectX, rectY, rectWidth, rectHeight);I need L tube, which connects the straight tubes. How to define L tubes?
- Write a program that draws line segmentsusing the arrow keys. The line starts from (100, 100) in the pane and drawstoward east, north, west, or south when the right-arrow key, up-arrow key, leftarrowkey, or down-arrow key is pressed, as shown in Figure .You have a mixed pile of N nuts and N bolts and need to quickly find the corresponding pairs of nuts and bolts. Each nut matches exactly one bolt, and each bolt matches exactly one nut. You can see which is larger by fitting a nut and bolt together, but it is not possible to directly compare two nuts or two bolts.You have a fence post located at the point (x,y) where a goat is tethered by a rope. You also have a house, which is a rectangle with diagonally opposite corners at the points bottom-left: (x1,y1) and top-right: (x2,y2). You want to pick a length of rope that guarantees the goat cannot reach the house. Determine the minimum distance from the fence post to the house, so that you can make sure to use a shorter rope. Recall that the distance formula is: sqrt( (x2−x1)^2+(y2−y1)^2 ) The input consists of a single line containing six space-separated integer values: x, y, x1, y1, x2, and y2. You are guaranteed that x1<x2 and y1<y2, and that (x,y) is strictly outside the axis-aligned rectangle with corners at (x1,y1) and (x2,y2). Return the minimum distance from the goat’s post to the house as a floating-point value from main(). Learning Objectives Be able to create a program with a lesser template. Be able to calculate the min/max of integers. Be able to write a mathematical…
- Your task: Remove any word that does not start with a capital letter. For instance, for the input text of "Hello, 2022 world!", we should get "Hello, 2022 !".Write a program to allow the user to calculate the distance between cities on a map. Sounds pretty complicated, eh? Don't worry, we'll make a few simplifications here: The distances are calculated in map units on the 2D map. Each city is given a set of coordinates relative to some point on the map. We'll call this origin (0,0). There can only be a finite number of cities in the system at a given time (you decide this maximum). But in order to make the system useful, we'll have to add a few other features: Each city has a name in addition to its coordinates (you can assume a maximum length for these names; but they must be able to hold spaces: Los Angeles, New York, etc.). The user selects what action to take from a menu: 1) Enter city Information 2) calculate Distance between two cities 3) Print All cities 4) Quit Make sure you allow them to choose their options by both the number and the capitalized letter(s) of the choice. They cannot calculate a distance until at least…This just colored the point I want coloring the line also please