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You need to make 0.500 L of a 60.0 mM CaCl2 solution from a 20.0 M CaCl2 stock solution. Determine how much stock solution and water you will need to make the dilute solution. Show your calculations.

Question
  1. You need to make 0.500 L of a 60.0 mM CaCl2 solution from a 20.0 M CaCl2 stock solution. Determine how much stock solution and water you will need to make the dilute solution. Show your calculations.
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Step 1

We have to calculate the volume of stock solution and water required to make 0.500 L of a 60.0 mM CaCl2 solution from a 20.0 M CaCl2 stock solution.

Step 2

On dilution, the amount of solute in the solution does not change. Therefore, Moles of CaCl2 in stock solution would be equal to the moles of CaCl2 in the diluted solution.

Moles of solute
Molarity
Volume of solution in L
:. Moles of solute = Molarity xVolume of solution in L
Now
Moles of CaCl, in stock solution = Moles of CaCl, in diluted solution
:. Molarity of stock solution(M) x Volume of stock solution in L (V)=
Molarity of diluted solution(M^) x Volume of diluted solution in L (V
i.e
M x V M V
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Moles of solute Molarity Volume of solution in L :. Moles of solute = Molarity xVolume of solution in L Now Moles of CaCl, in stock solution = Moles of CaCl, in diluted solution :. Molarity of stock solution(M) x Volume of stock solution in L (V)= Molarity of diluted solution(M^) x Volume of diluted solution in L (V i.e M x V M V

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Step 3

Now, calculate the volume of stock solution using

Ms = 20.0 M

Md = 60.0 mM = 60.0&...

M,x V M x V
М,xV,
V
м,
(60.0x10 M) x (0.500L) 1.5x103 L
V
(20.0 M)
Volume of water added to make diluted solution = 0.500 L - 0.0015 -0.4985 L
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M,x V M x V М,xV, V м, (60.0x10 M) x (0.500L) 1.5x103 L V (20.0 M) Volume of water added to make diluted solution = 0.500 L - 0.0015 -0.4985 L

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