Your protocol calls for a 0.15MM NaCl solution. How would you dilute your 3M NaCl solution to 0.15M as yourprotocol calls for? You can determine the overall dilution factor needed by dividing the final concentration(0.15mM NaCl), by the starting concentration (3M NaCI) (0.00015M/3M = 1/20,000).!!11. If you want to do this in 3 steps, what woul be three individual dilution factors you could use? Use asyour total volume 500 pl.12. What would be the concentration (in Molarity) for each of your three dilutions, individually? (Note:remember you started with 3M NaCI)

11) The total volume of the solution is 500μL(0.0005L) The concentration of the solution is 3M. We…

Your protocol calls for a 0.15MM NaCl solution. How would you dilute your 3M NaCl solution to 0.15M as your protocol calls for? You can determine the overall dilution factor needed by dividing the final concentration (0.15mM NaCI), by the starting concentration (3M NaCI) (0.00015M/3M = 1/20,000). %3! 11. If you want to do this in 3 steps, what would be three individual dilution factors you could use? Use as your total volume 500 ul. 12. What would be the concentration (in Molarity) for each of your three dilutions, individually? (Note: remember you started with 3M NaCI)

Your protocol calls for a 0.15MM NaCl solution. How would you dilute your 3M NaCl solution to 0.15M as your protocol calls for? You can determine the overall dilution factor needed by dividing the final concentration (0.15mM NaCI), by the starting concentration (3M NaCI) (0.00015M/3M = 1/20,000). %3! 11. If you want to do this in 3 steps, what would be three individual dilution factors you could use? Use as your total volume 500 ul. 12. What would be the concentration (in Molarity) for each of your three dilutions, individually? (Note: remember you started with 3M NaCI)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter4: Calculations Used In Analytical Chemistry

Section: Chapter Questions

Problem 4.24QAP

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