You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.7 m/s2. What is the minimum curvature radius to accommodate a 52-km/h maximum speed? Give your answer in meters I know the formula involves a= v^2/r and we get r by itself; and then, we are to find minimum curvature radius. My question has to do with a conversion of 52 km to meters, and yes, km=1000 m. Can you help me to conceptualize (52 km/h)^2 to (14.4 m/s)^2 better?
You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.7 m/s2. What is the minimum curvature radius to accommodate a 52-km/h maximum speed? Give your answer in meters I know the formula involves a= v^2/r and we get r by itself; and then, we are to find minimum curvature radius. My question has to do with a conversion of 52 km to meters, and yes, km=1000 m. Can you help me to conceptualize (52 km/h)^2 to (14.4 m/s)^2 better?
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 31P: Figure P3.31 represents the total acceleration of a particle moving clockwise in a circle of radius...
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You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.7 m/s2. What is the minimum curvature radius to accommodate a 52-km/h maximum speed? Give your answer in meters
I know the formula involves a= v^2/r and we get r by itself; and then, we are to find minimum curvature radius. My question has to do with a conversion of 52 km to meters, and yes, km=1000 m. Can you help me to conceptualize (52 km/h)^2 to (14.4 m/s)^2 better?
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