Yu = 10 k N/mJ = 14 kN/u²clayTsat = 15,5 kN/msDiagramraur3GWL-2.00Y = 16 kN/m3sandsat = 17 kN/m3sand Y=17 kN/m3Ysatt8,5 kN/u²Draw the diagrams of total stress, effective stress, and pore pressure regarding this case.

Total stress = Y*h Pore pressure=Yw*h Effective stress = total stress-pore pressure

Yu = 10 k N/m? J = 14 kN/u² clay Osat = 15,5 kN/ms Diagram 2 GWL -2.00 r = 16 kN/m³ sand I sut = 17KN/m3 %3D sand =17 kN/m3 Y sat 18,5kN/w raw the diagrams of total stress, effective stress, and pore pressure regarding this case.

Yu = 10 k N/m? J = 14 kN/u² clay Osat = 15,5 kN/ms Diagram 2 GWL -2.00 r = 16 kN/m³ sand I sut = 17KN/m3 %3D sand =17 kN/m3 Y sat 18,5kN/w raw the diagrams of total stress, effective stress, and pore pressure regarding this case.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter10: Stresses In A Soil Mass

Section: Chapter Questions

Problem 10.18P: Refer to the flexible loaded rectangular area shown in Figure 10.47. Using Eq. (10.36), determine...

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Concept explainers

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.

Question

Yu = 10 k N/m
J = 14 kN/u²
clay
Tsat = 15,5 kN/ms
Diagram
raur
3
GWL
-2.00
Y = 16 kN/m3
sand
sat = 17 kN/m3
sand Y=17 kN/m3
Ysatt8,5 kN/u²
Draw the diagrams of total stress, effective stress, and pore pressure regarding this case.

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