Зп 4 |cot x|csc?x dx 4

Q: Calcula te Y Sin X dX ,n=Lo by SimPSon rule

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Q: SHOW THAT : csc² (2 cot¯ /x -1 dx X - 1 Vx +x/x

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Q: sec® x dx cot x SE V

A: We can evaluate the given integral by using the substitution u= tan x and the following formulas.…

Q: [5 sec x tan x dx %3D

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Q: d (cot x) show that – csq² x. dx

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Q: | cos'x cot x dx 3.

A: To integrate the given.

Q: 1+cscx cotx integralf dx is ec X-CSCX

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Q: 5. Differentiate y = csc z(x + cot x).

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Q: 2- Evaluate sin x dx usin i. Trapezoidal rule ii. Simp

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Q: [3 cot.xsin x dk а.

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Q: Find and simplify th. dx cot x 1. y = 1+ cotx

A: Since you have asked multiple question As per our policy, we will solve the first question for you.…

Q: Stan (x)sec°(x)dx Scot*(x)csc°(x)dx Ssin*(x)cos°(x)dx

A: ∫tan5xsec6xdx

Q: 2. Find [cot (x)sin* (x)dx

A: First simplify then integrate

Q: 6- y" + 4y = cot(t)

A: Given:        y''+4y=cott        4yt+d2dt2yt=cott The differential has the form        y''+py'+qy=s…

Q: d (csc x) = -csc x cot x. dx Prove that

A: Given,          ddxcscx=-cscxcotx

Q: (tan V) (sec V) b) Evaluate dx

A: Given integral: I=∫tan4(x)sec2(x)xdx

Q: rind if, y² + x² = sin(xy) using implicit derivation dx

A: We will find the derivative.

Q: i tan?(x) sec(x) dx trig property 2.

A: We have to find the integration

Q: 2x dx by taking n = 4 1+ x Use trapezoidal Rule to evaluate

A: trapezoidal rule

Q: S sec (x)tan(x)dx =

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Q: Evaluate the integral.

A: Given: ∫01 tan-1x1+x2 dx To find: Value of the integral.

Q: cot ?/n (1 -x)dx 1-X

A: Integration is a reverse process of differentiation . Thus the integration is a process of finding…

Q: dx wherein x(2) = 4 り dy

A:

Q: |7t tan (1) dt

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Q: S 4 sec(x) tan(x) dx

A: We will use standard formula here

Q: 18. f(tan 2x + cot 2x)² dx

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Q: =8) S sec°(x)tan(x)dx =

A: Given∫sec6⁡(x)tan⁡(x)dxLetI=∫sec6⁡(x)tan⁡(x)dxI=∫sec5⁡(x)sec⁡(x)tan⁡(x)dx  — (1)

Q: Find dy/dx  if   x4= cot y

A: First diffrenciate with respect to x and y.. Then simplyfy.

Q: Find of xy = x + cot y dx

A: This Question need implicit differentiation

Q: 1/4 S (2 + sec)? dx

A: Please go through the attached solution. I hope that it  will help you .Thankyou . Best regards.

Q: 2. y In csc 3x – cot 3x| CS %3D

A: Given:- y = ln|csc(3x) - cot(3x)| To find:- Derivative of y

Q: 2x dx by taking n = 4. 1+x Use trapezoidal Rule to evaluate

A: on solving this we get

Q: ind dy/dx if y= xsquared-cotx-1divided by x squared show all work

A:

Q: Vsec z tan ædx = 3 O None O 2(sec æ) – }(sec æ)* +c 15 11 유(sec z) -5(sec z) +c -(sec 2) 3 + c 10…

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Q: 1. Cot cot x dy + ct x dx -x dx. xdx Sdx

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Q: I d (Cot x) (COS X dx sin X * Sin x (-sin x)-cos x (cos x) (Sinx) (sin*x + ças* x) Sinx + Cos x )…

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Q: Solve d²y cot x dx² dy - sin² dx sin²x.y = cos x - cos³

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Q: S tan“ x sec“ x dx

A: Given query is to find the value of the integral.

Q: S cot*xcsc*x dx

A: The given integral is ∫cot3 x csc4 x dx. Integrate as follows. ∫cot4 x csc4 x dx =∫cot4 x cot2+1…

Q: y - cot xy = cscx,

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Q: 2- Evaluate sin x dx using i. Trapezoidal rule ii. Simpson's rule iii. Simpson's rule, taking n = 6

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Q: 3 cSC x cot x dx

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Q: Use Trigonometric substitution to compute:

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Q: cot'(2) dx x+2 w.

A: Apply the identity cot2θ=csc2θ-1. So, ∫cot2x+23dx=∫csc2x+23dx-∫dx Consider ∫csc2x+23dx, Take…

Q: Evaluate [™ªx x cos(x) dx

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Q: 8. fx,y) = sinx cos y

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Q: Sinh メニ 2o COSN メー? Secnx =? tan h X=? Cotn X =?

A: Given, sinh x = 2099  We have to find cosh x,  sech x, tanh x , csch x  and  coth x.

Q: Let y dy/dx equals: cot x. cot x 2 cSc X 2. csc-x cot

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Q: 1 Evaluate: dx. 1+/cot x /6

A: Given: ∫π6π311+cot(x)dx