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Зx2 + x + 31 Вх + С + x2 +9 A (x + 4)(x² + 9) x + 4 A = B = С - Now evaluate the indefinite integral. Зx2 +x + 31 -dx = (x + 4)(x² + 9)

Зx2 + x + 31 Вх + С + x2 +9 A (x + 4)(x² + 9) x + 4 A = B = С - Now evaluate the indefinite integral. Зx2 +x + 31 -dx = (x + 4)(x² + 9)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.3: Algebraic Expressions
Problem 27E
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 The form of the partial fraction decomposition of a rational function is given below.

Зx2 + x + 31 Вх + С + x2 + 9 A (x + 4)(x² + 9) х+4 A = B = C = Now evaluate the indefinite integral. 3x2 + x + 31 (x + 4)(x² + 9)
Transcribed Image Text:Зx2 + x + 31 Вх + С + x2 + 9 A (x + 4)(x² + 9) х+4 A = B = C = Now evaluate the indefinite integral. 3x2 + x + 31 (x + 4)(x² + 9)
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