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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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Chapter
Section
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A rectangle has a length of (2.0 ± 0.2) m and a width of (1.5 ± 0.1) m. Calculate (a) the area and (b) the perimeter of the rectangle, and give the uncertainty in each value.

(a)

To determine
The area of the rectangle with uncertainty.

Explanation

Given info: The length of the rectangle is (2.0±0.2)m and the width of the rectangle is (1.5±0.1)m .

Explanation:

Formula to calculate the maximum area of the rectangle is,

Amax=LmaxWmax

  • Amax is maximum area,
  • Lmax is maximum length of the rectangle,
  • Wmax is the maximum width of the rectangle.

Substitute 2.2m for Lmax , 1.6m for Wmax to find Amax .

Amax=(2.2m)(1.6m)=3.52m2

Thus, the maximum area of rectangle (Amax) is 3.52m2

The minimum value of the area of the rectangle.

The formula to calculate the minimum value of the area of the rectangle is,

Amin=LminWmin

  • Amin is the minimum area,
  • Lmin is the minimum length of the rectangle,
  • Wmin is the minimum width of the rectangle.

Substitute 1.8m for Lmin , 1.4m for Wmin to find Amin .

Amin=(1.8m)(1

(b)

To determine
The perimeter of the rectangle.

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