Chapter 10, Problem 117AE

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404

Chapter
Section

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404
Textbook Problem

# Consider the following data for an unknown substance X:ΔHvap = 20.00 kJ/molΔHfus = 5.00 kJ/molSpecific heat capacity of solid 3.00 J/g °CSpecific heat capacity of liquid 2.50 J/g °CBoiling point = 75.0°CMelting point = 15.0°CMolar mass = 100.0 g/molIn the heating of substance X, energy (heat) is added at a constant rate of 450.0 J/min. At this rate, how long will it take to heat 10.0 g of X from −35.0eC to 25.0°C?

Interpretation Introduction

Interpretation:

The reaction rate (time) should be calculate given the unknown reaction with respective thermodynamic values.

Concept Introduction:

Gibbs free energy (G): The thermodynamic quantity to the ( ΔH) enthalpy of a system process and minutes the product of entropy and the absolute temperature. The energy associated with a chemical reaction that can be used to do work.  The free energy of a system is the sum of its enthalpy (H) plus the product of the temperature (Kelvin) and the entropy (S) of the system.

Thermal decomposition: This type of reaction caused by heat, or decomposition of substance is the temperature at which the substance chemically decomposes.

Vapor pressure (Kp): This is thermodynamic state function and the vapor-liquid equilibrium explain as the distribution of chemical species between the liquid phase to gas phase.

To find: The reaction rate time should be calculate given the unknown substance of given the statements.

Explanation

Calculate and analyze the reaction rate values of given unknown chemical (X) process.

The specific heat capacity of equation

X(s)â€‰+â€‰Heatâ€‰â‡Œâ€‰X(g)âˆ’âˆ’âˆ’âˆ’âˆ’âˆ’âˆ’âˆ’[âˆ’35.00Câ€‰toâ€‰25.00C]â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰X(heating)â€‰=Â Î”Hvap=4.64â€‰minE=mÃ—cÃ—Î¸âˆ’âˆ’âˆ’âˆ’âˆ’âˆ’[1]HereE=EnergyÂ (J),Â m=massÂ (kg),Â c=Â SpecificÂ heatÂ capacityÂ (J/C-1kg-1)<

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