Chapter 10, Problem 47P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# At what temperature would the rms speed of helium atoms equal (a) the escape speed from Earth, 1.12 × 104 m/s and (b) the escape speed from the Moon, 2.37 × 103 m/s? (See Topic 7 for a discussion of escape speed.) Note: The mass of a helium atom is 6.64 × 10−27 kg.

(a)

To determine
The temperature at which rms peed is equal to the escape velocity.

Explanation

Given info: Mass of helium molecule (m) is 6.64Ã—10âˆ’32â€‰kg . The escape velocity from earth ( vrms ) is 1.12Ã—104â€‰m/s .

Formula to calculate the temperature at which rms speed is equal to the escape velocity is,

T=mvrms23k

• m is the mass of helium molecule.
• k is the Boltzmann constant.
• vrms is the rms speed which is equal to the escape velocity.

Substitute 6.64Ã—10âˆ’32â€‰kg for m, 1.12Ã—104â€‰m/s for vrms and 1

(b)

To determine
The temperature at which rms peed is equal to the escape velocity.

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started