   Chapter 10, Problem 5P

Chapter
Section
Textbook Problem

On January 22, 1943, in Spearfish, South Dakota, the temperature rose from −4.00°F to 45.0°F over the course of two minutes (the current world record for the fastest recorded temperature change). By how much did the temperature change on the Kelvin scale?

To determine
The temperature change on Kelvin scale.

Explanation

Given Info: The temperature rose from T1=4.00οF and T2=45.0οF .

Formula to calculate the temperature on Kelvin scale is,

(T)K=59[(T)οF+459.67ο]       (I)

• T is the temperature.

On Differentiating Equation (I),

(ΔT)K=59[(ΔT)οF]       (II)

• ΔT is the change in temperature

The change in temperature on Fahrenheit scale is,

ΔT=T2T1

Substitute T2T1 for ΔT in Equation (II)

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