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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

Calculate the freezing point and the boiling point of each of the following solutions using the observed van’t Hoff factors in Table 10-6.

a. 0.050 m MgCl2

b. 0.050 m FeCl3

Interpretation Introduction

Interpretation: The freezing point and the boiling point of the given solutions are should be calculated.

Concept introduction:

  • Elevation of boiling point:

    The boiling point of the solution is increases when the solute is dissolved in the solvent is called Elevation of boiling point. it is one of the colligative Properties thus,

                                           ΔT=iKbmsolute......(1)ΔT is boiling-point elevationKbismolal boiling-point elevation constantmis molality of the soluteiisthevan't Hoff factor

  • Depression in freezing point:

    The freezing point the solution is decreases when the solute is dissolved in the solvent is called Elevation of boiling point. it is one of the colligative Properties thus

                                        ΔT=iKfmsolute......(2)ΔT is boiling-point elevationKfismolal freezing-point depression constantmis molality of the soluteiisthevan't Hoff factor

Explanation

Record the given data,

           Molality of MgCl2= 0.050m

           Molality of FeCl3=0.050m

To calculate the boiling point of 0.050mMgCl2 solution.

Molal boiling-point elevation constant of water is 0.51 °C/molal .

                          van't Hoff factor of MgCl2is2.7ΔT=2.7×0.51 °C/molal×0.050molal=0.069°C=100°C+0.069°CTb=100.069°C

  • The given values are plugging in to equation 1 to give elevation of boiling point this was added to boiling point of (solvent) water (100°C) to give the boiling point of 0.050mMgCl2 solution.
  • The boiling point of 0.050mMgCl2 solution is 100.069°C

To calculate the freezing point of 0.050mMgCl2 solution

Molal freezing-point depression constantof water is 1.86°C/molal

                                  van't Hoff factor of MgCl2is2.7ΔT=2.7×1.86 °C/molal×0.050molal=0.25°CTf=0.00°C-0.25°C=-25.0°C

  • The given values are plugging in to equation 1 to give depression in freezing point this was subtract from freezing point of (solvent) water (100°C) to give the boiling point of 0.050mMgCl2 solution

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