   Chapter 11, Problem 8P

Chapter
Section
Textbook Problem

An aluminum rod is 20.0 cm long at 20.0°C and has a mass of 0.350 kg. If 1.00 × 104 J of energy is added to the rod by heat, what is the change in length of the rod?

To determine
Change in length of the rod.

Explanation

Section1:

To determine: Change in temperature of the rod.

Answer: Change in temperature of the rod is 31.7°C .

Explanation:

Given Info: Heat energy added to the rod is 1.00×104J , mass of the rod 0.350 kg, and specific heat capacity of the rod is 900J/kg°C .

The formula to calculate the change in temperature is,

ΔT=Qmc

• Q is the heat energy added,
• m is the mass of the rod,
• c is the specific heat of the rod,
• ΔT is the change in temperature,

Substitute 1.00×104J for Q, 0.350 kg, and 900J/kg°C for c to find ΔT .

ΔT=1.00×104J(0.350kg)(900J/kg°C)=31.7°C

Thus, the change in the temperature of the rod is 31.7°C .

Section 2:

To determine: Change in length of the rod.

Answer: The length of the rod is 0

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