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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 12, Problem 40E
Textbook Problem
40 views

How many grams of glucose ( C 6 H 12 O 6 ) are present in 7.8 L of a 1.3-M glucose solution?

Interpretation Introduction

Interpretation:

The mass of glucose present in the given solution is to be calculated.

Concept Introduction:

The same solute and solvent can form a number of combinations by varying their amounts. These combinations can be differentiated in terms of concentration of solution. The amount of a solute present in a given amount of solvent is defined as its concentration.

The number of moles is calculated as follows:

Number of moles =Mass Molar mass

Molarity is the number of moles of solute present in one liter of a solution, and is expressed as follows:

Molarity=Number of molesVolume of solution

Explanation of Solution

Given Information: Molarity of glucose solution is 1.3 M. The volume of the solution is 7.8 L.

Molarity is defined as the number of moles of a solute present in 1L of a solution. The number of moles is calculated by the division of moles by molar mass as follows:

The number of moles is calculated using molarity as follows:

Molarity=Number of molesVolume of solution

Molarity=Number of moles of glucoseVolume of solution1.3 moles/L=Number of moles of glucose7.8 L Number of moles of glucose=1.3 moles/L×7.8L=10

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Chemistry In Focus
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