   Chapter 12, Problem 40P

Chapter
Section
Textbook Problem

A heat pump has a coefficient of performance of 3.80 and operates with a power consumption of 7.03 × 103 W. (a) How much energy does the heat pump deliver into a home during 8.00 h of continuous operation? (b) How much energy does it extract from the outside air in 8.00 h?

(a)

To determine
The energy that the pump deliver into home.

Explanation

Section 1:

To determine: The work input require for working the heat engine.

Answer: the work input require for working the heat engine is 2.10×108J

Explanation:

Given Info:

Power conception of the heat pump is 7.03×103W

Time of work of heat engine is 8h .

Formula to calculate the work input is,

W=P×Δt

• P is the power conception of the heat pump
• Δt is the time of work of heat engine

Substitute 7.03×103W for P and 8h for Δt to find the work input,

W=(7.03×103Js)(8.00h)(3600s1h)=2.10×108J

Thus, the work input require for working the heat engine is 2.10×108J

Conclusion:

From (a),

The work input require for working the heat engine is 2

(b)

To determine
the heat, the heat pump extracts from outside air in 8 h.

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