   Chapter 12, Problem 46P

Chapter
Section
Textbook Problem

A heat engine operates in a Carnot cycle between 80.0°C and 350°C. It absorbs 21 000 J of energy per cycle from the hot reservoir. The duration of each cycle is 1.00 s. (a) What is the mechanical power output of this engine? (b) How much energy does it expel in each cycle by heat?

(a)

To determine
The mechanical power output of the engine.

Explanation

Section 1:

To determine: To determine the efficiency of the Carnot engine.

Answer: The efficiency of the Carnot engine is 43.3% .

Explanation:

Given Info:

Temperature of the cold reservoir is 80°C .

Temperature of the hot reservoir is 350°C .

Formula to calculate the efficiency is,

ec=1TcTh

• Th is the temperature of the hot reservoir
• Tc is the temperature of the cold reservoir

Substitute 350°C for Th and 80°C for Tc to find the efficiency,

ec=1(80+273)K(350+273)K=0.433

Thus, the efficiency of the Carnot engine is 43.3% .

Conclusion:

From section 1, the efficiency of the Carnot engine is 43.3% .

The energy absorbed by system from the hot reservoir is 21000J .

The duration of each cycle is 1

(b)

To determine
To the energy that the engine expels in each cycle by heat.

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