   Chapter 13, Problem 36PS

Chapter
Section
Textbook Problem

A typical bottle of wine consists of an 11% solution (by weight) of ethanol (C2H5OH) in water. If the wine is chilled to −20 °C, will the solution begin to freeze?

Interpretation Introduction

Interpretation: It has to be identified whether the given solution begin to freeze at 20°C

Concept introduction:

Freezing point elevation: The freezing point of the solution varies with the solute concentration.

Depression in Freezing point = ΔTfp= Kfp. msolute,where,Kfpismolal boiling point elevation constant,msoluteis molality of solute

Explanation

Given data:

Massofethanolin 11%is=11g100gofsolution×100g=11gT=20°C

Numberofmole=MassofthesubstanceingramMolarmass

Mole of ethanol (solute) = 11g46.07g/mol=0.239mol;

Mass of Water = 100 g - 11 g89=0.089kg

Freezing point of water = 0oCKfpofWater =-1.86oC/m

Calculate the molality of solute  in solution(m):_molality = Moles of solute (mol)Amount of solvent(in kg) = (0

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