College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300



College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A supersonic jet traveling at Mach 3.00 at an altitude of h = 2.00 × 104 m is directly over a person at time t = 0 as shown in Figure P14.35. Assume the average speed of sound in air is 335 m/s over the path of the sound. (a) At what time will the person encounter the shock wave due to the sound emitted at t = 0? (b) Where will the plane be when this shock wave is heard?


To determine
The time when the shock wave reaches the observer.


Given Info: velocity of the plane is Mach 3.00

Formula to calculate the half-angle of the conical wave front is,


  • vsound is the velocity of the sound
  • vplane is the velocity of the plane

Mach 1.00 speed of aircraft in air is equal to the speed of sound in air. So, Mach 3.00 equals 3 times the speed of sound in air vplane=3vsound .

Substitute 335m/s for vsound and 3 vsound for vplane in the above expression to get θ


The below figure 1 shows the position of the Jet above the observe.

The below figure 2 shows the distance covered by the jet plane when the observer hears the shock wave.


To determine
  The distance of the plane when the shock is heard by the person.

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