   Chapter 15, Problem 26P

Chapter
Section
Textbook Problem

A helium nucleus of mass m = 6.64 × 10−27 kg and charge q = 6.41 × 10−19 C is in a constant electric field of magnitude E = 2.00 × 10−3 N/C pointing in the positive x-direction. Neglecting other forces, calculate (a) the nucleus’ acceleration and (b) its displacement after 3.00 s if it starts from rest.

(a)

To determine
The nucleus’ acceleration.

Explanation

Given info: The charge of the nucleus is 6.41×1019C . The mass of the nucleus is 6.64×1027kg . Electric field strength is 2.00×103N/C .

Formula to calculate the magnitude of acceleration of the proton is,

a=qEm

• q is the charge of nucleus.
• E is the electric field.
• m is the mass of proton.

Substitute 6.41×1019C for q, 2.00×103N/C for E and 6

(b)

To determine
The displacement after 3.00 s.

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