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ChemistryChemistry & Chemical Reactivity10th Edition

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Chapter 16, Problem 13PS
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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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Problem 93GQ
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Problem 95GQ
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Problem 99GQ
Problem 100GQ
Problem 101GQ
Problem 102GQ
Problem 103GQ
Problem 104GQ
Problem 105GQ
Problem 106GQ
Problem 107GQ
Problem 108GQ
Problem 109GQ
Problem 110GQ
Problem 111IL
Problem 112IL
Problem 113IL
Problem 114IL
Problem 115IL
Problem 116IL
Problem 117IL
Problem 118IL
Problem 119SCQ
Problem 120SCQ
Problem 121SCQ
Problem 122SCQ
Problem 123SCQ
Problem 124SCQ
Problem 125SCQ
Problem 126SCQ
Problem 127SCQ
Problem 128SCQ
Problem 129SCQ
BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

What is the pH of a 0.0015 M solution of Ba(OH)2?

Interpretation Introduction

Interpretation:

The pH of 0.0015 M solution of Ba(OH)2 has to be calculated.

Concept introduction:

pOH is a measure of hydroxide ion concentration, and pH is a measure of hydrogen ion concentration.

pOH=−log[OH−]

The sum of pH and pOH must be equal to 14 at 25 °C.

pH+pOH=14

Explanation

Beacause Ba(OH)2 is a strong base, it dissociates completely into ions in an aqueous solution as follows:

  Ba(OH)2⇌Ba+2+2OH−

Given:

The concentration of Ba(OH)2 in a solution is 0.0015 M.

The Ba(OH)2 after complete dissociation in an aqueous solution gives two moles of hydroxide ions, therefore the concentration of hydroxide ion is twice of concentration of Ba(OH)2.

[OH−]=2×0.0015 M=0.003 M

pOH is a measure of hydroxide ion concentration, and pH is a measure of hydrogen ion concentration.

pOH=−log[OH−]                                           �

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Sect-16.2 P-16.1CYUSect-16.4 P-16.2CYUSect-16.5 P-16.3CYUSect-16.7 P-16.4CYUSect-16.7 P-16.5CYUSect-16.7 P-16.6CYUSect-16.7 P-16.7CYUSect-16.7 P-16.8CYUSect-16.8 P-16.9CYUSect-16.10 P-1.1ACP
Sect-16.10 P-1.2ACPSect-16.10 P-1.3ACPSect-16.10 P-2.1ACPSect-16.10 P-2.2ACPSect-16.10 P-2.3ACPSect-16.10 P-2.4ACPSect-16.10 P-2.5ACPCh-16 P-1PSCh-16 P-2PSCh-16 P-3PSCh-16 P-4PSCh-16 P-5PSCh-16 P-6PSCh-16 P-7PSCh-16 P-8PSCh-16 P-9PSCh-16 P-10PSCh-16 P-11PSCh-16 P-12PSCh-16 P-13PSCh-16 P-14PSCh-16 P-15PSCh-16 P-16PSCh-16 P-17PSCh-16 P-18PSCh-16 P-19PSCh-16 P-20PSCh-16 P-21PSCh-16 P-22PSCh-16 P-23PSCh-16 P-24PSCh-16 P-25PSCh-16 P-26PSCh-16 P-27PSCh-16 P-28PSCh-16 P-29PSCh-16 P-30PSCh-16 P-31PSCh-16 P-32PSCh-16 P-33PSCh-16 P-34PSCh-16 P-35PSCh-16 P-36PSCh-16 P-37PSCh-16 P-38PSCh-16 P-39PSCh-16 P-40PSCh-16 P-41PSCh-16 P-42PSCh-16 P-43PSCh-16 P-44PSCh-16 P-45PSCh-16 P-46PSCh-16 P-47PSCh-16 P-48PSCh-16 P-49PSCh-16 P-50PSCh-16 P-51PSCh-16 P-52PSCh-16 P-53PSCh-16 P-54PSCh-16 P-55PSCh-16 P-56PSCh-16 P-57PSCh-16 P-58PSCh-16 P-59PSCh-16 P-60PSCh-16 P-61PSCh-16 P-62PSCh-16 P-63PSCh-16 P-64PSCh-16 P-65PSCh-16 P-66PSCh-16 P-67PSCh-16 P-68PSCh-16 P-69PSCh-16 P-70PSCh-16 P-71PSCh-16 P-72PSCh-16 P-73PSCh-16 P-74PSCh-16 P-75PSCh-16 P-76PSCh-16 P-77PSCh-16 P-78PSCh-16 P-79PSCh-16 P-80PSCh-16 P-81PSCh-16 P-82PSCh-16 P-83PSCh-16 P-84PSCh-16 P-85GQCh-16 P-86GQCh-16 P-87GQCh-16 P-88GQCh-16 P-89GQCh-16 P-90GQCh-16 P-91GQCh-16 P-92GQCh-16 P-93GQCh-16 P-94GQCh-16 P-95GQCh-16 P-96GQCh-16 P-97GQCh-16 P-98GQCh-16 P-99GQCh-16 P-100GQCh-16 P-101GQCh-16 P-102GQCh-16 P-103GQCh-16 P-104GQCh-16 P-105GQCh-16 P-106GQCh-16 P-107GQCh-16 P-108GQCh-16 P-109GQCh-16 P-110GQCh-16 P-111ILCh-16 P-112ILCh-16 P-113ILCh-16 P-114ILCh-16 P-115ILCh-16 P-116ILCh-16 P-117ILCh-16 P-118ILCh-16 P-119SCQCh-16 P-120SCQCh-16 P-121SCQCh-16 P-122SCQCh-16 P-123SCQCh-16 P-124SCQCh-16 P-125SCQCh-16 P-126SCQCh-16 P-127SCQCh-16 P-128SCQCh-16 P-129SCQ

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