   Chapter 16, Problem 1P

Chapter
Section
Textbook Problem

A uniform electric field of magnitude 375 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. After the electron has moved 3.20 cm, what is (a) the work done by the field on the electron, (b) the change in potential energy associated with the electron, and (c) the velocity of the electron?

(a)

To determine
The work done on the electron by the field.

Explanation

Given info: The displacement of the electron (x) is 3.20 cm. The electric field strength (E) is 375 N/C.

Explanation:

Formula to calculate the work done is,

W=eEx

• e is the elementary charge.

Substitute 1.6×1019C for e, 375 N/C for E and -3.20 cm for x.

W=(1.6×1019C)(375N/C)(3.20cm)=(1

(b)

To determine
The change in potential energy associated with the electron.

(c)

To determine
The velocity of electron.

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