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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

An alpha particle, which has charge 3.20 × 10−19 C, is moved from point A, where the electric potential is 3.60 × 103J/C, to point B. where the electric potential is 5.80 × 103 J/C. Calculate the work done by the electric field on the alpha particle in electron volts.

To determine
The work done by electric field.

Explanation

Given info: The charge on the nucleus is 3.20×1019C .

Explanation:

Formula to calculate the electric potential is,

W=q(ΔV)

  • ΔV is the potential difference.
  • q is the charge.

The potential difference is,

ΔV=(5.80×103J/C)(3.60×103J/C)=2.20×103J/C

Substitute 2.20×103J/C for ΔV and 3.20×1019C for q

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