9th Edition
Steven S. Zumdahl
ISBN: 9781133611097




9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

Calculate the solubility of solid Ca3(PO4)2 (Ksp = 1.3 × 10−32) in a 0.20-M Na3PO4 solution.

Interpretation Introduction

Interpretation: The solubility product of Ca3(PO4)2 is given. By using this value, the solubility of Ca3(PO4)2 is to be calculated in a given concentration of Na3PO4 solution.

Concept introduction: Solubility is defined as the maximum amount of solute that can dissolve at a certain amount of solvent at certain temperature. The solubility product, Ksp is the equilibrium constant that is applied when salt partially dissolve in a solvent. The solubility product of dissociation of AxBy is calculated as,



  • x is coefficient of concentration of A .
  • y is coefficient of concentration of B .


To determine: The solubility of Ca3(PO4)2 in 0.20M Na3PO4 .

The solubility of Ca3(PO4)2 in 0.20M Na3PO4 is 2.3×1011mol/L_ .


Solubility product of Ca3(PO4)2 is 1.3×1032 .

Concentration of Na3PO4 is 0.20M .

The dissociation reaction of Ca3(PO4)2 is,


The ratio of moles between ions is 3:2 .

Since, Na3PO4 is soluble in aqueous solution. The dissociation reaction of Na3PO4 is,


The concentration of PO4 is,


The solubility of Ca3(PO4)2 can be calculated from the concentration of ions at equilibrium.

It is assumed that smol/L of solid is dissolved to reach the equilibrium. The meaning of 3:2 stoichiometry of salt is,


Make the ICE table for the dissociation reaction of Ca3(PO4)2

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