A rock contains 0.308 mg 206Pb for every 1.000 mg 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206Pb is negligible, calculate the age of the rock. (The atomic mass of 206Pb is 205.97 u and the atomic mass of 238U is 238.05 u. For 238U, t1/2 = 4.5 x 109 years.) What is the age in years?
A rock contains 0.308 mg 206Pb for every 1.000 mg 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206Pb is negligible, calculate the age of the rock. (The atomic mass of 206Pb is 205.97 u and the atomic mass of 238U is 238.05 u. For 238U, t1/2 = 4.5 x 109 years.) What is the age in years?
Chapter19: The Nucleus: A Chemist's View
Section: Chapter Questions
Problem 76CWP
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A rock contains 0.308 mg 206Pb for every 1.000 mg 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206Pb is negligible, calculate the age of the rock. (The
What is the age in years?
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