# A proton moving at 4.00 × 10 6 m/s through a magnetic field of magnitude 1.70 T experiences a magnetic force of magnitude 8.20 × 10 −13 N. What is the angle between the proton’s velocity and the field?

### College Physics

11th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305952300

### College Physics

11th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305952300

#### Solutions

Chapter
Section
Chapter 19, Problem 9P
Textbook Problem

## A proton moving at 4.00 × 106 m/s through a magnetic field of magnitude 1.70 T experiences a magnetic force of magnitude 8.20 × 10−13 N. What is the angle between the proton’s velocity and the field?

Expert Solution
To determine
The angle between the proton’s velocity and the field.

### Explanation of Solution

Given info: The speed of the proton is 4.00×106ms-1 . The magnitude of the magnetic field is 1.70T . The magnetic force experienced by the proton is 8.20×1023N .

Explanation:

The magnetic force on a charged particle is given by,

F=qvBsinθ       (1)

• q is the charge on the particle
• v is the velocity of the particle
• B is the magnetic field
• θ is the angle between the velocity and the magnetic field

Solving for the angle θ ,

θ=sin1(FqvB)

Substitute 1.60×1019C for q , 4.00×106ms-1 for v , 1

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