   Chapter 2, Problem 27P

Chapter
Section
Textbook Problem

An object moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x-direction when its x-coordinate is 3.00 cm. If its x-coordinate 2-00 s later is −5.00 cm, what is its acceleration?

To determine
The acceleration of the object at 5.00cm .

Explanation

Given Info:

The initial velocity of the object is 12.0cm/s

The initial position of the object is 3.00cm

The final position of the object is 5.00cm

The time is 2.00s

Explanation:

The formula used to calculate the acceleration of the object is,

a=2(xfxi)v0tt2

• a is the acceleration
• xf is the final position of the object
• xi is the initial position of the object
• v0 is the initial velocity of the object
• t is the time required

Substitute 12cm/s for v0 , 3.00cm for xi , 5

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