   Chapter 2, Problem 36P

Chapter
Section
Textbook Problem

A record of travel along a straight path is as follows:1. Start from rest with a constant acceleration of 2.77 m/s2 for 15.0 s.2. Maintain a constant velocity for the next. 2.05 min.3. Apply a constant negative acceleration of −9.47 m/s2 for 4.39 s.(a) What was the total displacement for the trip?(b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip? trip, as well as for the complete trip?

(a)

To determine
The total displacement.

Explanation

Given Info: The initial velocity is 0 , the acceleration is 2.77m/s2 , the time is 15.0s , the constant velocity duration is 2.05min , and time period for negative acceleration is 4.39s .

Explanation:

The formula used to calculate the displacement is,

Δx1=v0t+12at2

Here,

Δx1 is the displacement

v0 is the initial velocity

a is the acceleration

t is time

Substitute 0 for v0 , 2.77m/s2 for a , and 15.0s for t to find Δx1 .

Δx1=(0)(15.0s)+12(2.77m/s2)(15.0s)2=312m

Thus, displacement at the first section is 312m .

The formula used to calculate the final velocity is,

v=v0+at

Here,

v is the final velocity

Substitute 0 for v0 , 2.77m/s2 for a , and 15.0s for t to find v .

v=(0)+(2.77m/s2)(15.0s)=41.6m/s

Thus, final velocity at the first section is 41.6m/s .

The formula used to calculate the displacement is,

Δx2=vt1

Here,

Δx2 is the displacement

v is the velocity

t1 is time

Substitute 41.6m/s for v and 2.05min for t1 to find Δx2 .

Δx2=(41.6m/s)((2.05min)(60s1min))=5

(b)

To determine
The average speeds for legs 1, 2, and 3 of the trip as well as complete trip.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 