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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A record of travel along a straight path is as follows:

1. Start from rest with a constant acceleration of 2.77 m/s2 for 15.0 s.

2. Maintain a constant velocity for the next. 2.05 min.

3. Apply a constant negative acceleration of −9.47 m/s2 for 4.39 s.

(a) What was the total displacement for the trip?

(b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip? trip, as well as for the complete trip?

(a)

To determine
The total displacement.

Explanation

Given Info: The initial velocity is 0 , the acceleration is 2.77m/s2 , the time is 15.0s , the constant velocity duration is 2.05min , and time period for negative acceleration is 4.39s .

Explanation:

The formula used to calculate the displacement is,

Δx1=v0t+12at2

Here,

Δx1 is the displacement

v0 is the initial velocity

a is the acceleration

t is time

Substitute 0 for v0 , 2.77m/s2 for a , and 15.0s for t to find Δx1 .

Δx1=(0)(15.0s)+12(2.77m/s2)(15.0s)2=312m

Thus, displacement at the first section is 312m .

The formula used to calculate the final velocity is,

v=v0+at

Here,

v is the final velocity

Substitute 0 for v0 , 2.77m/s2 for a , and 15.0s for t to find v .

v=(0)+(2.77m/s2)(15.0s)=41.6m/s

Thus, final velocity at the first section is 41.6m/s .

The formula used to calculate the displacement is,

Δx2=vt1

Here,

Δx2 is the displacement

v is the velocity

t1 is time

Substitute 41.6m/s for v and 2.05min for t1 to find Δx2 .

Δx2=(41.6m/s)((2.05min)(60s1min))=5

 (b)

To determine
The average speeds for legs 1, 2, and 3 of the trip as well as complete trip.

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