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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 2, Problem 43E
Textbook Problem
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Ethylene glycol (antifreeze) has a density of 1 .11 g/cm 3 .

a. What is the mass in g of 38 .5 mL of this liquid?

b. What is the volume in L of 3 .5 kg of this liquid?

Interpretation Introduction

Interpretation:

Mass and volume of different solutions of ethylene glycol are to be determined

Concept Introduction:

Density is defined as the ratio of mass and volume, or mass per unit volume. Mathematically, it is defined as:

density(d) = mass(m)volume(V)

Calculation of density(d) of a substance requires the division of its mass(m) by its volume(V). Therefore, the most commonly used units are:

 Gram per cubic meters (g/cm3)

 Gram per milliliter (g/mL)

Explanation of Solution

a) The mass in g of 38.5 mL of ethylene glycol.

The volume of ethylene glycol is 38.5mL and the density of ethylene glycol is 1.11g/cm3

The conversion of milliliter into cubic centimeter is as follows:

1 mL = 1 cm3

The above conversion shows that milliliter and cubic centimeter are equivalent units. Therefore, the conversion is as follows:

38.5 mL = 38.5 cm3

The mass of ethylene glycol is calculated as follows:

d= mVOr, m = d×V

Substitute, density = 1.11g/cm3 and volume = 38.5 cm3

m = 38.5cm3 × 1.11g1cm3    = 42.7 g

Hence, the density is 42.7 g.

b) The volume in L of 3.5 kg of ethylene glycol.

The mass of ethylene glycol is 3.5 kg and the density of ethylene glycol is 1.11g/cm3.

The conversion of kilogram (kg) into grams(g) is as follows:

1 kg = 1000 g

Therefore, the conversion factor of mass is as follows:

3.5 kg = 3.5kg × 1000g1kg            = 3500 g

The conversion of milliliter into cubic centimeter is as follows:

1 mL = 1 cm3

Therefore, the conversion factor of density is as follows:

1

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Chemistry In Focus
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