   Chapter 20, Problem 2P

Chapter
Section
Textbook Problem

Find the flux of Earth’s magnetic field of magnitude 5.00 × 10−5 T through a square loop of area 20.0 cm2 (a) when the field is perpendicular to the plane of the loop, (b) when the field makes a 30.0° angle with the normal to the plane of the loop, and (c) when the field makes a 90.0° angle with the normal to the plane.

(a)

To determine
The flux when the field is perpendicular to the plane of the loop.

Explanation

Given info: The magnetic field of earth (B) is 5.00×105T . Area of the square loop (A) is 20.0cm2 .

Formula to calculate flux is,

ϕB=BAcosθ

• θ is the angle between the field and area vector.

Substitute 5.00×105T for B, 20.0cm2 for A and 0ο for θ .

ϕB=(5.00×105T)(20

(b)

To determine
The flux when the field makes a 30ο angle with the normal to the plane of the loop.

(c)

To determine
The flux when the field makes a 90ο angle with the normal to the plane of the loop.

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