dq dE dE2 a x. dEx dE dEL dE b Figure 23.3 (Example 23.2) A uniformly charged ring of radius a. (a) The field at Pon the x axis due to an element of charge dq. (b) The perpendicular component of the field at Pdue to segment 1 is canceled by the perpendicular component due to segment 2. a

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Chapter1: Units, Trigonometry. And Vectors
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Show that the maximum magnitude Emax of the electric field along the axis of a uniformly charged ring occurs at x = a/√2 (as shown) and has the value Q/(6√3π∈0a2).

dq
dE dE2
a
x.
dEx
dE
dEL
dE
b
Figure 23.3 (Example 23.2) A uniformly charged ring of radius a. (a) The field at
Pon the x axis due to an element of charge dq. (b) The perpendicular component of
the field at Pdue to segment 1 is canceled by the perpendicular component due to
segment 2.
a
Transcribed Image Text:dq dE dE2 a x. dEx dE dEL dE b Figure 23.3 (Example 23.2) A uniformly charged ring of radius a. (a) The field at Pon the x axis due to an element of charge dq. (b) The perpendicular component of the field at Pdue to segment 1 is canceled by the perpendicular component due to segment 2. a
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