A cosmic-ray proton in interstellar space has an energy of 12.5 MeV and executes a circular orbit having a radius equal to that of Mars' orbit around the Sun (2.28 × 1011 m). What is the magnetic field (in T) in that region of space? Hint: Fc =FB mv2 = gvB this will give you B = r mv = : now think K.E = gr where K.E can be expressed in terms of Momentum (mv) where p qr and K.E is given in the question but you need to convert that into the Joule (1 eV = 1.6 × 10-19 /) and mass of proton is 1.67× 10¬27 Kg Hope you can do this with this hint
A cosmic-ray proton in interstellar space has an energy of 12.5 MeV and executes a circular orbit having a radius equal to that of Mars' orbit around the Sun (2.28 × 1011 m). What is the magnetic field (in T) in that region of space? Hint: Fc =FB mv2 = gvB this will give you B = r mv = : now think K.E = gr where K.E can be expressed in terms of Momentum (mv) where p qr and K.E is given in the question but you need to convert that into the Joule (1 eV = 1.6 × 10-19 /) and mass of proton is 1.67× 10¬27 Kg Hope you can do this with this hint
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Transcribed Image Text:A cosmic-ray proton in interstellar space has an energy of 12.5 MeV and executes a circular orbit having a radius equal to that of Mars' orbit around the
Sun (2.28 x 10" m). What is the magnetic field (in T) in that region of space?
Hint:
Fc = FB
mv
mv
= qvB this will give you B
qr
think K.E = mv²,
now
where K.E can be expressed in terms of Momentum (mv) where p
%3D
r
gr
7 Kg
and K.E is given in the question but you need to convert that into the Joule (1 eV =1.6 × 10-19 /) and mass of proton is 1.67x 10-27
Hope you can do this with this hint
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