Answered: The square loop in Figure P31.26 is…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

The square loop in Figure P31.26 is made of wires with total series resistance 10.0 Ω. It is placed in a uniform 0.100-T magnetic field directed perpendicularly into the plane of the paper. The loop, which is hinged at each corner, is pulled as shown until the separation between points A and B is 3.00 m. If this process takes 0.100 s, what is the average current generated in the loop? What is the direction of the current?

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Expert Solution

Step 1

Given:

Uniform magnetic field B = 0.1 T

Total series resistance $R = 10.0 Ω$

Length of wire $l = 3 m .$

time taken t = 0.1 s.

Step 2

Induced E.M.F. is given as,

$ε = - N \frac{d ϕ}{d t} ε = - N \frac{d}{d t} B A \cos θ = - N \frac{d}{d t} B A \cos 0 ε = - N B \frac{d A}{d t} ε = - 1 \times 0.1 \times \frac{(A_{f} - A_{i})}{0.1} ε = - (3 \times 3 \sin 60 - 3^{2}) ε = 1.206 v o l t$

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