Chapter 4, Problem 41PS

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

What is the mass of solute, in grams, in 250, mL of a 0.0125 M solution of KMnO4?

Interpretation Introduction

Interpretation:

The mass of solute, in grams, in 250mL of a 0.0125M solution of KMnO4 should be determined.

Concept introduction:

• Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
• Molarity (M) of a solution is the number of gram moles of a solute present in one litre of the solution.

Molarity=MassperlitreMolecular mass

• A solution containing one gram mole or 0.1 gram of solute per litre of solution is called molar solution.
• Amount of substance (mol) can be determined by using the equation,

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
Explanation

The mass of solute, in grams, in 250â€‰â€‰mL of a 0.0125â€‰M solution of KMnO4 is 0.494â€‰g.

Molar concentration of given KMnO4 solution is 0.0125â€‰â€‰M and the volume of the solution in litre is .250â€‰L.

Before to find the mass of solute in gram, the amount of KMnO4 required to make above concentrated solution has to be determined.

Thus,

Amount of KMnO4 required = .250â€‰Lâ€‰Ã—0.0125â€‰molâ€‰ofâ€‰â€‰KMnO4â€‰1â€‰â€‰Lâ€‰solutionâ€‰â€‰=â€‰0

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