   Chapter 4, Problem 41PS

Chapter
Section
Textbook Problem

What is the mass of solute, in grams, in 250, mL of a 0.0125 M solution of KMnO4?

Interpretation Introduction

Interpretation:

The mass of solute, in grams, in 250mL of a 0.0125M solution of KMnO4 should be determined.

Concept introduction:

• Concentration of solutions can be expressed in various terms; molarity is one such concentration expressing term.
• Molarity (M) of a solution is the number of gram moles of a solute present in one litre of the solution.

Molarity=MassperlitreMolecular mass

• A solution containing one gram mole or 0.1 gram of solute per litre of solution is called molar solution.
• Amount of substance (mol) can be determined by using the equation,

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
Explanation

The mass of solute, in grams, in 250mL of a 0.0125M solution of KMnO4 is 0.494g.

Molar concentration of given KMnO4 solution is 0.0125M and the volume of the solution in litre is .250L.

Before to find the mass of solute in gram, the amount of KMnO4 required to make above concentrated solution has to be determined.

Thus,

Amount of KMnO4 required = .250L×0.0125molofKMnO41Lsolution=0

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