Chapter 4, Problem 68PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# What volume of 0.125 M oxalic acid, H2C2O4, is required to react with 35.2 mL of 0.546 M NaOH?H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2H2O(l)

Interpretation Introduction

Interpretation:

The volume of 0.125M oxalic acid H2C2O4 required to react with 35.2mLof 0.546MNaOH has to be determined.

Concept introduction:

• Numberofmole=GivenmassofthesubstanceMolarmass
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).

Molarity=Amountofsolute(mol)Volumeofsolution(L)

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
Explanation

Balanced chemical equation for the given reaction is,

â€‚Â H2C2O4(aq)â€‰+â€‰2â€‰NaOH(aq)â€‰â†’â€‰Na2C2O4(aq)â€‰+â€‰2H2O(l)

AmountÂ ofÂ NaOHÂ inÂ 35.2Â mLÂ ofÂ 0.546Â MÂ NaOH = 0.0352â€‰â€‰Lâ€‰Ã—â€‰0.546â€‰M = 0.0192â€‰molesâ€‰

By using the stoichiometric factor calculating the amount of H2C2O4 required based on the amount of NaOH as follows,

â€‚Â 0.0192molâ€‰NaOHâ€‰Ã—1â€‰molâ€‰H2C2O42molâ€‰NaOHâ€‰â€‰=â€‰0

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