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Chapter 4, Problem 69PS
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### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# What volume of 0.812 M HCI, in milliliters, is required to titrate 1.45 g of NaOH to the equivalence point?NaOH(aq) + HCl(aq) → H2O(l) + NaCI(aq)

Interpretation Introduction

Interpretation:

The volume of 0.812MHCl in milliliters, required to titrate 1.45g of NaOH to the equivalence point has to be determined.

Concept introduction:

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
• Concentrationofsubstance=Amountof substancevolumeofthesubstance
• Amountof substance=Concentrationofsubstance×volumeofthesubstance
• Volumeofthesubstance=Amountof substanceConcentrationofsubstance
Explanation

Balanced chemical equation for the given reaction is,

â€‚Â NaOH(aq)â€‰+â€‰HCl(aq)â€‰â†’â€‰NaCl(aq)+â€‰H2Oâ€‰(l)

The amount (moles) of NaOH available can be calculated as follows,

â€‚Â 1.45â€‰gâ€‰NaOHâ€‰Ã—1â€‰molâ€‰NaOH40â€‰gâ€‰â€‰=â€‰0.03625â€‰molâ€‰NaOH

The balanced equation for the reaction shows that 1â€‰mol of NaOH Â requires 1â€‰mol of HCl

This is the required stoichiometric factor to obtain the amount of HCl present.

Thus the amount of HCl can be calculated as follows,

â€‚Â 0.03625molâ€‰NaOHâ€‰Ã—â€‰1â€‰molâ€‰HCl1molâ€‰NaOHâ€‰=â€‰0

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