   Chapter 5, Problem 3P

Chapter
Section
Textbook Problem

A cable exerts a constant upward tension of magnitude 1.25 × 104 N on a 1.00 × 103-kg elevator as it rises through a vertical distance of 2.00 m. (a) Find the work done by the tension force on the elevator. (b) Find the work done by the force of gravity on the elevator.

(a)

To determine
The work done by the tension force on the elevator.

Explanation

Given Info:

The tension exerted by the cable on the elevator is 1.25×104N .

The mass of elevator is 1.00×103kg

The vertical distance that elevator rise is 2.00m .

Formula to calculate the work done by the tension force is,

WT=(Tcosθ)d

• θ is the angle between the vectors T and d
• T is the tension
• d is the vertical displacement

Since, the tension force and the displacement is in the direction upward, the angle θ is zero.

Substitute 1.25×104N for T, zero for θ and 2

(b)

To determine
The work done by the force of gravity on the elevator.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 