   Chapter 5, Problem 61RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Evaluating a Definite Integral In Exercises 59–70, evaluate the definite integral. ∫ − 1 1 ( 4 t 3 − 2 t 3 )   d t

To determine

To calculate: The definite integral 11(4t32t3)dt.

Explanation

Given Information:

The provided definite integral is 11(4t32t3)dt.

Formula used:

The sum and difference property of definite integrations:

ab[f(x)±g(x)]dx=ab[f(x)]dx±ab[g(x)]dx

The power rule of integrals:

undu=un+1n+1+C

The fundamental theorem of calculus:

abf(x)dx=F(b)F(a)

Here, F is function such that F(x)=f(x) for all x in [a,b].

Calculation:

Consider the indefinite integral:

11(4t32t3)dt

Now apply, the property of definite integrations:

11(4t32t3)dt=411(t3)dt211(t1

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